How to use
- Fill in Currency code, Distance per year, Interval, Oil cost, Filter cost, Labour for Oilchanges.
- To match “12,000 per year at a 5,000 interval”, enter Currency code USD; Distance per year 12000; Interval 5000; Oil cost 35; Filter cost 12; Labour 20.
- Press Calculate. The summary line should be “Oilchanges: 3 scheduled changes, USD 201.00”.
- Read every line under “Oilchanges: 3 scheduled changes, USD 201.00” before you copy the Oilchanges result.
- Press Copy for the whole Oilchanges result, or Reset to restore “12,000 per year at a 5,000 interval”.
- For the second check, “An interval that divides evenly”, the summary should be “Oilchanges: 2 scheduled changes, USD 100.00”.
Formula / how it works
Example “12,000 per year at a 5,000 interval” sets Currency code = USD; Distance per year = 12000; Interval = 5000; Oil cost = 35; Filter cost = 12; Labour = 20.
Oilchanges returns this exact text:
Oilchanges: 3 scheduled changes, USD 201.00
12000 ÷ 5000 = 2.40 intervals. Each change USD 67.00 (oil USD 35.00, filter USD 12.00, labour USD 20.00).
The budget uses the rounded-up count.
Example “An interval that divides evenly” sets Currency code = USD; Distance per year = 6000; Interval = 3000; Oil cost = 40; Filter cost = 10; Labour = 0.
Oilchanges returns this exact text:
Oilchanges: 2 scheduled changes, USD 100.00
6000 ÷ 3000 = 2.00 intervals. Each change USD 50.00 (oil USD 40.00, filter USD 10.00, labour USD 0.00).
6,000 divided by 3,000 is two changes.
Oilchanges vocabulary for this page: oil, interval, filter, mileage, service, oilchanges.
Oilchanges pass 1 (“An interval that divides evenly”) prints:
Oilchanges: 2 scheduled changes, USD 100.00
6000 ÷ 3000 = 2.00 intervals. Each change USD 50.00 (oil USD 40.00, filter USD 10.00, labour USD 0.00).
The words for this pass are oil, interval, filter, mileage, service, oilchanges.
Worked examples
12,000 per year at a 5,000 interval
Inputs: Currency code: USD | Distance per year: 12000 | Interval: 5000 | Oil cost: 35 | Filter cost: 12 | Labour: 20
Set Currency code USD, then Distance per year 12000, then Interval 5000, then Oil cost 35, then Filter cost 12, then Labour 20. Press Calculate. The Oilchanges summary should read “Oilchanges: 3 scheduled changes, USD 201.00”.
Result: Oilchanges: 3 scheduled changes, USD 201.00
12000 ÷ 5000 = 2.40 intervals. Each change USD 67.00 (oil USD 35.00, filter USD 12.00, labour USD 20.00).
The budget uses the rounded-up count.
An interval that divides evenly
Inputs: Currency code: USD | Distance per year: 6000 | Interval: 3000 | Oil cost: 40 | Filter cost: 10 | Labour: 0
Set Currency code USD, then Distance per year 6000, then Interval 3000, then Oil cost 40, then Filter cost 10, then Labour 0. Press Calculate. The Oilchanges summary should read “Oilchanges: 2 scheduled changes, USD 100.00”.
Result: Oilchanges: 2 scheduled changes, USD 100.00
6000 ÷ 3000 = 2.00 intervals. Each change USD 50.00 (oil USD 40.00, filter USD 10.00, labour USD 0.00).
6,000 divided by 3,000 is two changes.
Use cases
- Check “Oilchanges: 3 scheduled changes, USD 201.00” before trusting a new Oilchanges input.
- Check “Oilchanges: 2 scheduled changes, USD 100.00” as the second Oilchanges case.
- The budget uses the rounded-up count.
- 6,000 divided by 3,000 is two changes.
Tips & limitations
- “12,000 per year at a 5,000 interval”: The budget uses the rounded-up count.
- “An interval that divides evenly”: 6,000 divided by 3,000 is two changes.
- Oilchanges fields: Currency code, Distance per year, Interval, Oil cost, Filter cost, Labour.
- The Oilchanges summary for the opening example is “Oilchanges: 3 scheduled changes, USD 201.00”.
FAQ
What does “12,000 per year at a 5,000 interval” return?
Oilchanges summary: “Oilchanges: 3 scheduled changes, USD 201.00”. Full result: Oilchanges: 3 scheduled changes, USD 201.00 12000 ÷ 5000 = 2.40 intervals. Each change USD 67.00 (oil USD 35.00, filter USD 12.00, labour USD 20.00).
What does “An interval that divides evenly” return?
Oilchanges summary: “Oilchanges: 2 scheduled changes, USD 100.00”. Full result: Oilchanges: 2 scheduled changes, USD 100.00 6000 ÷ 3000 = 2.00 intervals. Each change USD 50.00 (oil USD 40.00, filter USD 10.00, labour USD 0.00).
Which values produce “Oilchanges: 3 scheduled changes, USD 201.00”?
Currency code: USD | Distance per year: 12000 | Interval: 5000 | Oil cost: 35 | Filter cost: 12 | Labour: 20
Which values produce “Oilchanges: 2 scheduled changes, USD 100.00”?
Currency code: USD | Distance per year: 6000 | Interval: 3000 | Oil cost: 40 | Filter cost: 10 | Labour: 0
How is “Oilchanges: 3 scheduled changes, USD 201.00” different from “Oilchanges: 2 scheduled changes, USD 100.00”?
“12,000 per year at a 5,000 interval” gives “Oilchanges: 3 scheduled changes, USD 201.00”. “An interval that divides evenly” gives “Oilchanges: 2 scheduled changes, USD 100.00”.
What does Oilchanges include in the full first result?
Oilchanges: 3 scheduled changes, USD 201.00 12000 ÷ 5000 = 2.40 intervals. Each change USD 67.00 (oil USD 35.00, filter USD 12.00, labour USD 20.00).
Results are calculated from the values you enter. Double-check measurements and allow a margin before buying materials or making decisions.